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How much heat is required to change 10g ...

How much heat is required to change `10g` ice at `0^(@)C` to steam at `100^(@)C`? Latent heat of fusion and vaporisation for `H_(2)O` are `80 cl g^(-1)` and `540 cal g^(-1)`, respectively. Specific heat of water is `1cal g^(-1)`.

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Total heat absorbed
`=DeltaH_("fusion")+DeltaH_("temp. rise")+DeltaH_(vap)`.
`=10xx80+10xx1xx100+10xx540=7200cal`
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How much heat is required to change 10g ice at 10^(@)C to steam at 100^(@)C ? Latent heat of fusion and vaporisation for H_(2)O are 80 cl g^(-1) and 540 cal g^(-1) , respectively. Specific heat of water is 1cal g^(-1) .

How much heat is required to change 10g ice at 0∘Cto steam at 100∘ C ? Latent heat of fusion and vaporisation for H_(2)O are 80calg^(-1) and 540calg^(-1) ,respectively.Specific heat of water is 1calg^(-1)

How much heat is required to change 5 gram ice (0^@C) to steam at 100^@C ? Latent heat of fusion and vaporization for water are 80 cal/g and 540 cal/g respectively . Specific heat of water is 1 cal/ g/k.

Steam at 100°C is passed into 100 g of ice at 0°C . Finally when 80g ice melts the mass of water present will be [Latent heat of fusion and vaporization are 80 cal g^(-1) and 540 cal g^(-1) respectively, specific heat of water = 1 cal g^(-1) °C^(-1) ]

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