Calculate the resonance enegry of `N_(2)O` form the following data
`Delta_(f)H^(Theta) of N_(2)O = 82 kJ mol^(-1)`
Bond enegry of `N-=N, N=N, O=O,` and `N=O` bond is `946, 418, 498`, and `607 kJ mol^(-1)`, respectively.

Explanation

`N-=N(g)+(1)/(2)(O=O)toN=N=O(g)`
`=(946+(1)/(2)xx498)-(607+418)`
`=1195-1025=170` kJ `mol^(-1)`
resonance energy=Observed heat of formation`~`Calculated heat of formation
`=82~170=88kJ``mol^(-1)`