The enthalpies for the following reactions `(DeltaH^(Theta))` at `25^(@)C` are given below.
a. `(1)/(2)H_(2)(g) +(1)/(2)O_(2)(g) rarr OH(g)`
`DeltaH = 10.06 kcal`
b. `H_(2)(g) rarr 2H(g), DeltaH = 104.18 kcal`
c. `O_(2)(g) rarr 2O(g), DeltaH = 118.32 kcal`
Calculate the `O-H` bond energy in the hydroxyl radical.

Explanation

Required equation is
`H(g)+O(g)toO-H(g)`, `DeltaH=?`
Given, `(1)/(2)H_(2)(g)+(1)/(2)O_(2)(g)toOH(g)," "DeltaH=+10.06kcal`
`H(g)to(1)/(2)H_(2)(g)," "DeltaH=-52.09kcal`
`O(g)to(1)/(2)O_(2)(g)," "DeltaH=-59.16kcal`
Adding, `H(g)+O(g)to OH(g)," "DeltaH=-101.19kcal`