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The enthalpy change DeltaH for the neutr...

The enthalpy change `DeltaH` for the neutralisation fo `1M HCI` by caustic potash in dilute solution at `298 K` is

A

68kJ

B

65 kJ

C

57.3 kJ

D

50 kJ

Text Solution

Verified by Experts

The correct Answer is:
C
Since, both HCl and KOH are strong, 57.3 kJ heat will be released.
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OP TANDON-Chemical Thermodynamics and Thermochemistry-Illustrations of Objective Questions
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