Enthalpy of neutralisation of the reaction between `CH_(3)COOH(aq)` and `NaOH(aq)` is `-13.2kcal Eq^(-1)` and that of the reaction between `H_(2)SO_(4)(aq)` and `KOH (aq)` is `-13.7 kcal Eq^(-1)`. The enthalpy of dissociation of `CH_(3)COOH(aq)` is

Options

A. `-0.5` kcal `eq^(-1)`
B. `+0.5` kcal `eq^(-1)`
C. `-26.9kcal` `eq^(-1)`
D. `+13.45kcal` `eq^(-1)`

Answer

B

Explanation

Dissociation enthalpy of `CH_(3)COOH=13.7-13.2=0.5kcal` `eq^(-1)`. Thus, 0.5 kcal `eq^(-1)` heat will be used to dissociate `CH_(3)COOH` completely.