Equal volumes of `1M HCI` and `1M H_(2)SO_(4)` are neutralised by `1M NaOH` solution and `x` and `y kJ//` equivalent of heat are liberated, respectively. Which of the following relations is correct?

Options

A. `x=2y`
B. `x=3y`
C. `x=4y`
D. `x=1//2y`

Answer

D

Explanation

Since, `H_(2)SO_(4)` gives 2 moles `H^(+)` while HCl gives 1 mole `H^(+)` from 1 mole after ionisation. Hence, `H_(2)SO_(4)` will release double amount of heat as compared to HCl.
i.e., `y=2x` or `x=(y)/(2)`