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For the reaction: 2H(2)(g) +O(2)(g) ra...

For the reaction:
`2H_(2)(g) +O_(2)(g) rarr 2H_(2)O(g), DeltaH =- 571 kJ`
bond enegry of `(H-H) = 435 kJ` and of `(O=O) = 498 kJ`. Then, calculate the average bond enegry of `(O-H)` bond using the above data.

A

484 kJ

B

`-484kJ`

C

`271kJ`

D

`-271kJ`

Text Solution

Verified by Experts

The correct Answer is:
A
`2(H-H)+O=Oto2(H-O-H)`
`DeltaH=sum(BE)_("reactants")-sum(BE)_("products")`
`=571=[2xx435+498]-4xx(BE)_(O-H)`
`(BE)_(O-H)=(2xx435+498+571)/(4)=~~484kJ`
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