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The heat of combustion of ethane gas is ...

The heat of combustion of ethane gas is `-368 kcal mol^(-1)`. Assuming that `60%` of heat is useful, how many `m^(3)` of ethane measured at `NTP` must be burned to supply heat to convert `50 kg` of water at `10^(@)C` to steam at `100^(@)C`?

Text Solution

Verified by Experts

Heat required per gram of water
`=(90+540)cal=630cal`
Total heat needed for 50 kg of water
`=50xx10^(3)xx630cal`
As the efficiency is 60%, the actual amount of heat required
`=(50xx10^(3)xx630)/(60)xx100=52500kcal`
No. of mole of ethane required to produce 52500 kcal
`=(52500)/(368)=142.663xx22.4`
`=3195.65`litre`=3.195m^(3)`
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