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Enthalpy of fusion of water is 6.01 kJ m...

Enthalpy of fusion of water is 6.01 kJ `mol^(-1)`. The entropy change of 1 mole of ice at its melting point will be:

A

22kJ `mol^(-1)`

B

109 kJ `mol^(-1)`

C

44 kJ `mol^(-1)`

D

11 kJ `mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaS_(fusion)=(DeltaH_(fusion))/(T_(mp))=(6.01xx1000)/(273)=22kJ` `mol^(-1)`.
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