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In the reaction A^(+)+BtoA+B^(+) there i...

In the reaction `A^(+)+BtoA+B^(+)` there is no entropy change. If enthalpy change is 22 kJ of `A^(+)`, calculate `DeltaG` for the reaction.

Text Solution

Verified by Experts

For the given reaction,
`DeltaH=22kJ,DeltaS=0`
`therefore` From `DeltaG=DeltaH-TDeltaS`
`DeltaG=22-Txx0=22kJ" "mol^(-1)`
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