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For the homogeneous reactions: xA+yBto...

For the homogeneous reactions:
`xA+yBtolY+mZ`
`DeltaH=-30kJ" "mol^(-1),DeltaS=-100JK^(-1)" "mol^(-1)`
At what temperature the reaction is at equilibrium?

A

`50^(@)C`

B

`250^(@)C`

C

`100K`

D

`27^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
D
`DeltaG=DeltaH-TDeltaS`
At equilibrium `DeltaG=0`
`thereforeT=(DeltaH)/(DeltaS)=(-30xx1000)/(-100)=300K,` i.e., `27^(@)C`.
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