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For the equilibrium, PCI(5)(g) hArr PC...

For the equilibrium,
`PCI_(5)(g) hArr PCI_(3)(g) +CI_(2)(g) at 25^(@)C K_(c) =1.8 xx 10^(-7)`
Calculate `DeltaG^(Theta)` for the reaction `(R = 8.314 J K^(-1) mol^(-1))`.

Text Solution

Verified by Experts

We know that
`DeltaG^(@)=-2.303RTlogK_(C)`
`=-2.303xx8.314xx298log(1.8xx10^(-7))`
`=38484J" "mol^(-1)=38.484kJ" "mol^(-1)`
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