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Equilibrium constant for the reaction: ...

Equilibrium constant for the reaction:
`H_(2)(g) +I_(2) (g) hArr 2HI(g) is K_(c) = 50 at 25^(@)C`
The standard Gibbs free enegry change for the reaction will be:

A

`-6.964kJ`

B

`-9.694kJ`

C

`-4.964kJ`

D

`-6.496kJ`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaG^(@)=-2.303RT" log "K_(C)`
`=-2.303xx8.314xx298" log "50`
`=-9694J=-9.694kJ`
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