Calculate `DeltaH` at `85^(@)C` for the reaction:
`Fe_(2)O_(3)(s) +3H_(2)(g) rarr 2Fe(s) +3H_(2)O(l)`
The data: `DeltaH_(298)^(Theta) =- 33.0 kJ mol^(-1)` and `{:("Substance",Fe_(2)O_(3)(s),Fe(s),H_(2)O(l),H_(2)(g)),(C_(P)^(@)(JK^(-1)mol),103.0,25.0,75.0,28.0):}`

Explanation

`Fe_(2)O_(3)(s)+3H_(2)to2Fe+3H_(2)O`
`DeltaC_(P)=(C_(P))_(P)-(C_(P))_(R)`
`=(2xx25.1+3xx75.3)-(103.8+3xx28.8)`
`=276.1-190.2=85.9J`
`(DeltaH_(T_(2))-DeltaH_(T_(1)))/(T_(2)-T_(1))=DeltaC_(P)`
`(DeltaH_(358)-(-33.29))/(358-298)=85.9xx10^(-3)`
`DeltaH_(358)=-28.14kJ//mol`