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For the conversion of 1 mole of SO(2)(g)...

For the conversion of 1 mole of `SO_(2)(g)` into `SO_(3)(g)` the enthalpy of reaction at constant volume. `DeltaU`, at 298 K is `-97.027kJ`. Calculate the enthalpy of reaction, `DeltaH`, at constant pressure.

Text Solution

Verified by Experts

The correct Answer is:
`DeltaH=-98.267J`
Use the rection,
`SO_(2)(g)+(1)/(2)O_(2)(g)toSO_(3)(g),Deltan=1-(3)/(2)=-(1)/(2)`.
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