1 mole of naphthalene (C(10)H(8)) was bu...

1 mole of naphthalene `(C_(10)H_(8))` was burnt in oxygen gas at `25^(@)C` at constant volume. The heat evolved was found to be 5138.8kJ. Calculate the heat of reaction at constant pressure.
`(R=8.3JK^(-1)" "mol^(-1))`

Text Solution

Verified by Experts

The correct Answer is:

5143.8kJ

Water is present in liquid state at `25^(@)C` and naphthalene in solid state.

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