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Calculate the entropy of ideal mixing wh...

Calculate the entropy of ideal mixing when 2 m oles of `N_(2)`, 3 moles of `H_(2) and 2` moles of `NH_(3)` are mixed at constant temperature, assuming no chemical reaction is occurring.

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To calculate the entropy of ideal mixing for the given gases, we will follow these steps: ### Step 1: Identify the number of moles of each component We have: - \( N_2 \): 2 moles - \( H_2 \): 3 moles - \( NH_3 \): 2 moles ### Step 2: Calculate the total number of moles Total moles \( N_{total} \) can be calculated as: \[ N_{total} = N_{N_2} + N_{H_2} + N_{NH_3} = 2 + 3 + 2 = 7 \text{ moles} \] ### Step 3: Calculate the mole fraction of each component The mole fraction \( X_i \) for each component is calculated using the formula: \[ X_i = \frac{N_i}{N_{total}} \] Calculating for each component: - For \( N_2 \): \[ X_{N_2} = \frac{2}{7} \] - For \( H_2 \): \[ X_{H_2} = \frac{3}{7} \] - For \( NH_3 \): \[ X_{NH_3} = \frac{2}{7} \] ### Step 4: Use the formula for entropy change of ideal mixing The formula for the entropy change \( \Delta S \) for ideal mixing is given by: \[ \Delta S = -R \sum (N_i \log X_i) \] Where \( R \) is the universal gas constant, approximately \( 8.314 \, \text{J/mol·K} \). ### Step 5: Substitute the values into the formula Now substituting the values: \[ \Delta S = -R \left( N_{N_2} \log X_{N_2} + N_{H_2} \log X_{H_2} + N_{NH_3} \log X_{NH_3} \right) \] Substituting the values: \[ \Delta S = -8.314 \left( 2 \log \frac{2}{7} + 3 \log \frac{3}{7} + 2 \log \frac{2}{7} \right) \] ### Step 6: Calculate each term Calculating each logarithm: - \( \log \frac{2}{7} \) - \( \log \frac{3}{7} \) Using a calculator: - \( \log \frac{2}{7} \approx -0.3567 \) - \( \log \frac{3}{7} \approx -0.1552 \) Now substituting these values back: \[ \Delta S = -8.314 \left( 2 \times (-0.3567) + 3 \times (-0.1552) + 2 \times (-0.3567) \right) \] Calculating: \[ \Delta S = -8.314 \left( -0.7134 - 0.4656 - 0.7134 \right) \] \[ \Delta S = -8.314 \left( -1.8924 \right) \] \[ \Delta S \approx 15.73 \, \text{J/K} \] ### Final Result The entropy of ideal mixing for the given gases is approximately: \[ \Delta S \approx 15.73 \, \text{J/K} \]

To calculate the entropy of ideal mixing for the given gases, we will follow these steps: ### Step 1: Identify the number of moles of each component We have: - \( N_2 \): 2 moles - \( H_2 \): 3 moles - \( NH_3 \): 2 moles ...
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