The reaction, `SOCl_(2)+H_(2)OtoSO_(2)+2HCl`, is endothermica by 49.4 kJ and exergonic by 50.8 kJ. What is ht efactor that makes the reaction to be spontaneous? Calculate the entropy change at 298K.

Answer

`DeltaS^(@)=0.3372kJ" "K^(-1)`

Explanation

Exergonic means `DeltaG^(@)=-ve`.
`DeltaG^(@)=-50.8kJ`
`DeltaH^(@)=49.4kJ`
substitute these values in `DeltaG^(@)=DeltaH^(@)-TDeltaS^(@)` to calculate entropy.
`DeltaS^(@)=(DeltaH^(@)-DeltaG^(@))/(T)=(49.4-(-50.8))/(298)`
`=0.3362kJ" "K^(-1)`