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Consider the reaction: N(2) + 3H(2) hArr...

Consider the reaction: `N_(2) + 3H_(2) hArr 2NH_(3)` carried out at constant pressure and temperature. If `DeltaH` and `DeltaU` are change in enthalpy and change in internal energy respectively, then:

A

`DeltaH=0`

B

`DeltaH=DeltaU`

C

`DeltaH lt DeltaU`

D

`DeltaH gt DeltaU`

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaH=DeltaU+DeltanRT,Deltan=2-4=-2`
`thereforeDeltaH lt DeltaU`
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