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The amount of heat released when 20 ml,0...

The amount of heat released when `20 ml`,`0.5 M` `NaOH`is mixed with `100 ml`,`0.1 M` `H_(2)SO_(4)` is `xKJ`. The heat of neutralization will be `:-`

A

`-100x`

B

`-50x`

C

`+100x`

D

`+50x`

Text Solution

Verified by Experts

The correct Answer is:
A
Number of moles of `NaOH=(MV)/(1000)=(0.5xx20)/(1000)=0.01`
Number of moles of `HCl=(MV)/(1000)=(0.1xx100)/(1000)=0.01`
Heat of neutralization `=(-x)/(0.01)=-100x`
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