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Dissociation of sodium azide is given be...

Dissociation of sodium azide is given below:
`NaN_(3)toNa+3//2N_(2),`
`DeltaH` for this is:

A

`3//2DeltaH_(f(N_(2)))^(@)-DeltaH_(f(NaN_(3)))^(@)`

B

`DeltaH_(f(NaN_(3)))^(@)`

C

`DeltaH_(f(NaN_(3)))^(@)-[DeltaH_(f(Na))^(@)+3//2DeltaH_(f(N_(2)))^(@)]`

D

`DeltaH_(f(Na))^(@)+3//2DeltaH_(f(N_(2)))^(@)-DeltaH_(f(NaN_(3)))^(@)`

Text Solution

Verified by Experts

The correct Answer is:
B
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