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For a particular reaction, DeltaH=-38.3 ...

For a particular reaction, `DeltaH=-38.3 kJ and DeltaS^(@)=-113JxxK^(-1).` This reaction is:

A

spontaneous at all temperature

B

non-spontaneous at all temperature

C

spontaneous at temperature below `66^(@)C`

D

spontaneous at temperature above `66^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
D
`DeltaG=DeltaH-TDeltaS`
For spontaneous process, `DeltaG lt 0`
`(DeltaH)/(DeltaS) lt T`
`(-38.3xx1000)/(-113) lt T`
i.e., `T gt 338.93K`, i.e., `66^(@)C`
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