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One gram mole of graphite and diamond we...

One gram mole of graphite and diamond were burnt to form `CO_(2)` gas:
`C_(("graphite"))+O_(2)(g)toCO_(2)(g)," "DeltaH^(@)=-399.5kJ`
`C_(("diamond"))+O_(2)(g)toCO_(2)(g)," "DeltaH^(@)=-395.4 kJ`

A

graphite is more stable than diamond

B

diamond is more stable than graphite

C

graphite has greater affinity with oxygen

D

diamond has greater affinity with oxygen.

Text Solution

Verified by Experts

The correct Answer is:
A
Thermal stability of one isotope is directly proportional to the heat of combustion.
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Calculate the DeltaH in joules for C("graphite")toC("diamond") from the following data: C("graphite")+O_(2)(g)toCO_(2)(g):" "DeltaH^(@)=-393.5kJ C("diamond")+O_(2)(g)toCO_(2)(g)," "DeltaH^(@)=-395.4kJ

The heat of transition (Delta H_(t)) of graphite into diamond would be, where C (graphite) +O_(2)(g)to CO_(2)(g) , Delta H = x kJ C (diamond) +O_(2)(g)to CO_(2)(g) , Delta H = y kJ

C_("graphite")+O_(2)(g)rarrCO_(2)(g) deltaH=-94.05Kcalmol^(-1) C_("diamond")+O_(2)(g),DeltaH=-94.50Kcalmol^(-1) Therefore,

Calculate the enthalpy of combustion of glucose from the follwoing data : C("graphite") +O_(2)(g) to CO_(2)(g) Delta_(r)H^(@) = -395.0 kJ H_(2)(g) + 1/2 O_(2)(g) to H_(2)O(l) Delta_(r)H^(@) = - 269.4 kJ 6C("graphite") + 6H_(2)(g) + 3O_(2)(g) to C_(6)H_(12)O_(6)(s) Delta_(r)H^(@) = -1169.9 kJ

The equation C (graphite) +O_(2)(g) CO_(2)(g) Delta H=-395.5kJ can be reversed as CO_(2)(g) rarr C ("graphite")+O_(2) gas DeltaH= +395.5 kJ This is called as

Determine the heat of transformaiton of C_(("dimamond"))rarrC_(("graphite")) form the following data: i. C_(("diamond"))+O_(2)(g) rarr CO_(2)(g), DeltaH^(Theta) =- 94.5 kcal ii. C_(("graphite")) +O_(2)(g) rarr CO_(2)(g),DeltaH^(Theta) =- 94.0 kcal

Determine Delta U^(@) at 300K for the following reaction using the listed enthalpies of reaction : 4CO(g)+8H_(2)(g)to3CH_(4)(g)+CO_(2)(g)+2H_(2)O(l) C("graphite")+(1)/(2)O_(2)(g)to CO(g), DeltaH_(1)^(@)=-110.5KJ CO(g)(1)/(2)O_(2)(g)toCO_(2)(g), DeltaH_(2)^(@)=-282.9KJ H_(2)(g)+(1)/(2)O_(2)(g)to H_(2)O(l), DeltaH_(3)^(@)=-285.8KJ C("graphite")+2H_(2)(g)to CH_(4)(g), DeltaH_(4)^(@)=-74.8KJ

OP TANDON-Chemical Thermodynamics and Thermochemistry-Objective Question Level B
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