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A change in the free energy of a system ...

A change in the free energy of a system at constant temperature and pressure will be:
`Delta_(sys)G = Delta_(sys)H -T Delta_(sys)S`
At constant temperature and pressure
`Delta_(sys) G lt 0` (spontaneous)
`Delta_(sys)G = 0` (equilibrium)
`Delta_(sys)G gt 0` (non-spontaneous)
The free enegry for a reaction having `DeltaH = 31400 cal, DeltaS = 32 cal K^(-1) mol^(-1) at 1000^(@)C` is

A

`-9336cal`

B

`-7386cal`

C

`-1936cal`

D

`+9336cal`

Text Solution

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The correct Answer is:
A
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The free energy for a reaction having DeltaH=31400 cal, DeltaS=32" cal "K^(-1)mol^(-1) at 1000^(@)C is:

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