Home
Class 12
CHEMISTRY
5g of K(2)SO(4) are dissolved in 250mL o...

5g of `K_(2)SO_(4)` are dissolved in 250mL of solution. How many mL of this solution should be used so that 1.2 of `BaSO_(4)` may be precipated from `BaCl_(2)` solution?

Text Solution

Verified by Experts

The desired equation is
`BaCl_(2)+underset(=174g)underset(2xx39+32+64)(K_(2)SO_(4)) to underset(=223g)underset(137+32+64)(BaSO_(4))+2KCl`
`233g of BaSO_(4)` obtained from 174g of `K_(2)SO_(4)`
1.2 of `BaSO_(4)` will be obtained from `(174)/(233)xx1.2`
`=0.8961"g of "K_(2)SO_(4)`
So, 0.891g of `K_(2)SO_(4)` will be present in `(250)/(5)xx0.8961`
`=44.8"mL of solution"`
Promotional Banner

Topper's Solved these Questions

  • STOICHIOMETRY (CHEMICAL FORMULAE AND EQUATIONS )

    OP TANDON|Exercise IILLUSTRATION|23 Videos

  • STOICHIOMETRY (CHEMICAL FORMULAE AND EQUATIONS )

    OP TANDON|Exercise Practical Problems|23 Videos

  • SATURATED ALIPHATIC HYDROCARBONS

    OP TANDON|Exercise SINGLE INTEGER ANSWER TYPE QUESTIONS|7 Videos

  • UNSATURATED HYDROCARBONS

    OP TANDON|Exercise SINGLE INTEGER ANSWER TYPE QUESTIONS|10 Videos

Similar Questions

Explore conceptually related problems

5 g of K_(2)SO_(4) was dissolved in 250 ml of solution. How many ml of this solution sholuld be used so that 2.33 g of BaSO_(4) may be precipitated from BaCl_(2) solution. K_(2)SO_(4)+BaCl_(2)rarrBaSO_(4)+2KCl

Fill in the blanks. a. The equivalent weight of NaHCO_(3) is ……..and of SO_(2) is ……… b. 2 mol of 50% pure Ca(HCO_(3))_(2) on heating forms 1 mol of CO_(2) . The % yield of CO_(2) is …….. c. 5 g of K_(2) SO_(4) was dissolved in 250 mL of solution. The volume of this solution that should be used so that 1.2 g of BaSO_(4) be precipitated fromk BaCl_(2) is ....... (molecular mass of K_(2) SO_(4) = 174 and BaSO_(4) = 233 ) d. The residue obtained on strongly heating 2.76 g Ag_(2) CO_(3) is ........ [Ag_(2)CO_(3) overset(Delta)rarr Ag + CO_(2) + O_(2)] Atomic mass of Ag = 108

5 gm of K_2 SO_4 solution were dissolved in 250 ml of water. How many ml of this solution are needed to precipitate out 1.2 gm of BaSO_4 on addition of BaCI_2 ?

If 100 mL of 1NH_(2)SO_(4) is mixed with 100 mL of 1 M NaOH solution. The resulting solution will be

0.7g of (NH_(4))_(2)SO_(4) sample was boiled with 100mL of 0.2 N NaOH solution was diluted to 250 ml. 25mL of this solution was neutralised using 10mL of a 0.1 N H_(2)SO_(4) solution. The percentage purity of the (NH_(4))_(2)SO_(4) sample is :

A difinite amount of BaCl_(2) was dissolved in HCl solution of unknown normality. 20 " mL of " this solution was treated with 21.4 " mL of " 01 N NaOH, for complete neutralisation. Further 20 " mL of " the solution was added to 50 " mL of " 0.1 N Na_(2)CO_(3) and the precipitate was filtered off. The filtrate reacted with 10.5 " mL of " 0.08 N H_(2)SO_(4) using phenolphthalein as indicator. Calculate the strength of BaCl_(2) in mixture.

How many grams of H_(2)SO_(4) are present in 500ml of 0.2M H_(2)SO_(4) solution ? .

4.0 g of NaOH and 4.9 g of H_(2)SO_(4) are dissolved in water and volume is made upto 250 mL. The pH of this solution is: