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KI+I(2)+HNO(3) to HIO(3)+KIO(3)+NO(2) ...

`KI+I_(2)+HNO_(3) to HIO_(3)+KIO_(3)+NO_(2)`
If 3 moles of KI and 2 moles of `I_(2)` are mixed with excess `HNO_(3)` then volume of `NO_(2)` gas evolved at NTP is:

A

716.8litre

B

1075.2litre

C

44.8litre

D

67.2litre

Text Solution

Verified by Experts

The correct Answer is:
a
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