How long has a current of 3 ampere to be applied through a solution of silver nitrate to coat a metal surface of `80 cm^(2)` with 0.005 mm thick layer ? Density of silver is `10.5 g//cm^(3)`.

Explanation

To solve the problem, we need to determine how long a current of 3 amperes must be applied to deposit a silver layer of specified thickness on a given area. Here are the steps to arrive at the solution:

### Step 1: Calculate the volume of silver to be deposited

The thickness of the silver layer is given as 0.005 mm. We need to convert this thickness into centimeters for consistency with the area measurement.

\[
\text{Thickness in cm} = 0.005 \, \text{mm} \times \frac{1 \, \text{cm}}{10 \, \text{mm}} = 0.0005 \, \text{cm}
...