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An aqueous solution of NaCl on electroly...

An aqueous solution of `NaCl` on electrolysis gives `H_(2)(g), Cl_(2)(g),` and `NaOH` accroding to the reaction `:`
`2Cl^(c-)(aq)+2H_(2)Orarr2overset(c-)(O)H(aq)+H_(2)(g)+Cl_(2)(g)`
A direct current of `25A` with a current efficiency of `62%` is passed through `20L` of `NaCl` solution `(20%` by weight`)`. Write down the reactions taking place at the anode and cathode. How long will it take to produce `1 kg ` of `Cl_(2)`? What will be the molarity of the solution with respect to hydroxide ion ? `(` Assume no loss due to evaporation . `)`

Text Solution

Verified by Experts

Reaction at anode and cathode are :
`2Cl^(-) rarr Cl_(2)+2e^(-) ("at anode")`
`2H_(2)O+2e^(-) rarr H_(2) + 2OH^(-) ("at cathode")`
1 kg of `Cl_(2)=1000/71.0=14.08` mole
Charge to produce one mole of `Cl_(2)=2xx96500` coulomb
Charge to produce 14.08 mole of `Cl_(2)=2xx96500xx 14.08` coulomb
Effective current `=62/100xx25.0=15.5` ampere
Time`=("Charge")/("Current")=(2xx96500xx14.08)/(15.5)`
`=175318.7` second `=48.699` hour
`OH^(-)` ions produced `=2xx" moles of "Cl_(2)`
`=2xx14.08=28.16` mole
Molarity `=("Mole")/("Volume")=28.16/20=1.408 M`
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