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The specific conductivity of 0.02 M KCl ...

The specific conductivity of 0.02 M KCl solution at `25^(@)C` is `2.768xx10^(-3) ohm^(-1) cm^(-1)`. The resistance of this solution at `25^(@)C` when measured with a particular cell was 250.2 ohm. The resistance of 0.01 M `CuSO_(4)` solution at `25^(@)C` measured with the same cell was 8331 ohm. Calculate the molar conductivity of the copper sulphate solution.

Text Solution

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Cell constant `=("Sp. Cond. Of KCl")/("Conductance of KCl")`
`=(2.768 xx 10^(-3))/(1//250.2)`
`=2.768xx10^(-3)xx250.2`
For 0.01 M `CuSO_(4)` solution
Sp. Conductivity = Cell constant `xx` Conductance
`=2.768xx10^(-3) xx250.2xx1/8331`
Molar conductance =Sp. cond. `xx1000/C`
`=(2.768xx10^(-3)xx250.2)/(8331)xx1000/(1//100) =8.312 ohm^(-1) cm^(2) mol^(-1)`
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