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The equivalent conductivity of N/10 solu...

The equivalent conductivity of N/10 solution of acitic acid at `25^(@)C` is `14.3 ohm^(-1) cm^(2) eq^(-1)`. Calculate the degree of dissociation of `CH_(3)COOH` if `Lambda_(oo CH_(3)COOH)` is 390.71.

Text Solution

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`Lambda_(oo CH_(3)COOH)=390.71 ohm^(-1) cm^(2) eq^(-1)`
`Lambda_(CH_(3)COOH)=14.3 ohm^(-1) cm^(2) eq^(-1)`
Degree of dissociation, `alpha=Lambda_(v)/Lambda_(oo) =14.3/390.71`
`=0.0366`, i.e., 3.66 % dissociated
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