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A decinormal solution of NaCl has specif...

A decinormal solution of `NaCl` has specific conductivity equal to `0.0092`. If ionic conductances of `Na^(+)` and `Cl^(-)` ions at the same temperature are 43.0 and `65.0 ohm^(-1)` respectively, calculate the degree of dissociation of NaCl solution.

Text Solution

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Equivalent conductance of N/10 NaCl solution
`Lambda_(v)=` Sp. Conductivity `xx` dilution
`=0.0092xx10,000=92 ohm^(-1)`
`Lambda_(oo)=lambda_(Na^(+))+lambda_(Cl^(-))`
`=43.0+65.0=108 ohm^(-1)`
Degree of dissociation, `alpha=Lambda_(v)/Lambda_(oo)=92/108=0.85`
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