What is the single electrode potential of a half-cell for zinc electrode dipping in 0.01 M `ZnSO_(4)` solution at `25^(@)C` ? The standard electrode potential of `Zn//Zn^(2+)` system is 0.763 volt at `25^(@)C`.

Explanation

We know that, `E_(o x)=E_(o x)^(@)-0.0591/n log_(10) ["ion"]`
Putting the value of `E_(o x)^(@)=0.763 V, n=2` and `[Zn^(2+)]=0.01 M`,
`E_(o x)=0.763-0.0591/2 log_(10) [0.01]`
`=0.763-0.02955xx(-2)`
`=(0.763+0.0591)` volt `=0.8221` volt