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Calculate the emf of the cell. Mg(s)|M...

Calculate the emf of the cell.
`Mg(s)|Mg^(2+) (0.2 M)||Ag^(+) (1xx10^(-3))|Ag`
`E_(Ag^(+)//Ag)^(@)=+0.8` volt, `E_(Mg^(2+)//Mg)^(@)=-2.37` volt
What will be the effect on emf If concentration of `Mg^(2+)` ion is decreased to `0.1 M` ?

Text Solution

Verified by Experts

`E_(cell)^(@)=E_("Cathode")^(@)-E_("Anode")^(@)`
`=0.80-(-2.37)=3.17` volt
Cell reaction, `Mg+2Ag^(+) rarr 2Ag +Mg^(2+)`
`E_(cell)=E_(cell)^(@)-0.0591/n log (Mg^(2+))/([Ag^(+)]^(2))`
`=3.17-0.0591/2 log 0.2/([1xx10^(-3)]^(2))`
`=3.17-0.1566=3.0134` volt
when `Mg^(2+)=0.1 M`
`E_(cell)=E_(cell)^(@)-0.0591/2 "log"0.1/((1xx10^(-3))^(2))`
`=(3.17-0.1477)` volt
`=3.0223` volt
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