Home
Class 12
CHEMISTRY
Calculate the pH of the following half-c...

Calculate the pH of the following half-cells solutions :
(a) `PtH_(2) ("1 atm")|H^(+) (HCl), " "E=0.25" volt"`
(b) `PtH_(2) ("1 atm")|H^(+) (H_(2)SO_(4))," "E=0.3" volt"`

Text Solution

Verified by Experts

(a) `H_(2) rarr 2H^(+)+2e`
`E_(H_(2)//H^(+))=E_(H_(2)//H^(+))^(@)-0.0591/2"log" ([H^(+)]^(2))/P_(H_(2))`
`=0.0-0.0591 "log" ([H^(+)])/1`
`0.25=0.0591 pH`
`pH=0.25/0.0591=4.23`
(b) `E_(H_(2)//H^(+))=E_(H_(2)//H^(+))^(@)-0.0591/2"log" ([H^(+)]^(2))/P_(H_(2))`
`=0.0-0.0591 "log" ([H^(+)])/(1)`
`0.3=0.0591 pH`
`pH=0.3/0.0591=5.076`
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    OP TANDON|Exercise ILLUSTRATIONS|28 Videos
  • ELECTROCHEMISTRY

    OP TANDON|Exercise PRACTICE PROBLEMS|94 Videos
  • COORDINATION COMPOUNDS

    OP TANDON|Exercise SBJECTIVE TYPE|96 Videos
  • HALOALKANES AND HALOARENES

    OP TANDON|Exercise Single Interger answer type questions|14 Videos

Similar Questions

Explore conceptually related problems

Calculate the pH of the following half cells solutions and also the molarity of acids: {: (Pt_(H_(2))),(atm):}|{:H_(2)SO_(4):} " " E = 0.05 (b) {: (Pt_(H_(2))),(atm):}|{:HCl:} " " E = 0.1 V

Calculate EMF of the following half cells : a. Pt, H_(2)(2 atm)|HCl(0.02M)" "E^(c-)=0V b. Pt , Cl_(2)(10 atm)|HCl(0.1 M)" "E^(-c)=1.36V

Calculate pH of the half cell : Pt,H_(2)(1 atm)|H_(2)SO_(4)" "E^(c-)=-0.3V

Find the electrode potentials of the following electrodes. (a) Pt, H_2 (1 atm)/HCl (0.1 M), (b) Pt, H_2 (2 atm)/ H_2SO_4 (0.01 M)

The pH of LHE in the following cell is : Pt, H_(2)(1atm)|H^(o+)(x M)||H^(o+)(0.1M)|H_(2)(0.1atm)Pt E_(cell)=0.295V .

Calculate the reduction potential of the following electrodes : a. Pt,H_(2)(4 atm)|H_(2)SO_(4)(0.01M) b. Pt,H_(2)(1 atm)| HCl (0.2 M) c. Calculate the potential of hydrogen electrode in contact with a solution whose i pH=5" "ii. pOH=4

Write Nernst equation and calculate e.m.f of the following cells at 298 K : Sn (s) |Sn^(2+) (0.050 M) ||H^(+) (0.020 M) |H_(2) (1atm) | Pt Given : E_((Sn^(2+) | Sn))^(Theta) = -0.14 V