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Find the equilibrium constant that the r...

Find the equilibrium constant that the reaction
`In^(2+)+Cu^(2+)underset(larr)rarrIn^(3+)+Cu^(+)` at 298 K
Given
`E_(Cu^(2+)//Cu^(+))=0.15V, E_(In^(2+)//In^(+))^(@)=-0.40V`
`E_(In^(3+)//In^(+))^(@)=+0.42V`

Text Solution

Verified by Experts

The given reversible reaction can be obtained as,
`{:(Cu^(2+)+e^(-) rarr Cu^(+)," "DeltaG^(@)=-0.15F :' DeltaG^(@)=-nFE^(@)),(In^(2+)+e^(-) rarr In^(+)," "DeltaG^(@)=+0.40 F),(" "In^(+) rarr In^(3+) +2e^(-)," "DeltaG^(@)=-0.84 F),(ulbar(Cu^(2+)+In^(2+) hArr In^(3+) + Cu^(+)," "DeltaG^(@)=-0.59 F)):}`
`-nFE^(@)=-0.59 F`
`E^(@)=0.59" volt"`
Equilibrium constant can be calculate as,
`K=" antilog"[(nE^(@))/0.059]`
`=" antilog"[(1xx0.59)/0.059]=10^(10)`
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