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1L of 1M CuSO(4) solution is electrolyze...

`1L` of `1M CuSO_(4)` solution is electrolyzed using `Pt` cathode and `Cu` anode. After passing `2F` of electricity, the `[Cu^(2+)]` will be

A

`M//2`

B

`M//4`

C

`M`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
D
2F charge will deposit 2 equivalent or 1 mole of copper
`Cu^(2+)+2e^(-) rarr Cu`
Thus, all the copper from `CuSO_(4)` solution will be deposied and molarity of remaining `CuSO_(4)` solution will be zero.
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