Equivalent conductances of `NaCl, HCl` and `CH_(3)COONa` at infinite dilution are 126.45, 426.16 and 91 `ohm^(-1) cm^(2) eq^(-1)` respectively. The equivalent conductance of `CH_(3)COOH` at infinite dilution would be :

Options

A. `101.38 ohm^(-1) cm^(2) eq^(-1)`
B. `253.62 ohm^(-1) cm^(2) eq^(-1)`
C. `390.71 ohm^(-1) cm^(2) eq^(-1)`
D. `678.90 ohm^(-1) cm^(2) eq^(-1)`

Answer

C

Explanation

`Lambda_(CH_(3)COOH)^(@)=Lambda_(CH_(3)COONa)^(@)+Lambda_(HCl)^(@)-Lambda_(NaCl)^(@)`
`=91+426.16-126.45`
`=390.71 ohm^(-1) cm^(2) eq^(-1)`