The resistance of `1N` solution of acetic acid is `250ohm`, when measured in a cell of cell constant `1.15 cm^(-1)`. The equivalent conductance `(` in `ohm^(-1) cm^(2)eq^(-1))` of `1N` acetic acid is

Options

A. `4.6 ohm^(-1) cm^(2) eq^(-1)`
B. `9.2 ohm^(-1) cm^(2) eq^(-1)`
C. `18.4 ohm^(-1) cm^(2) eq^(-1)`
D. `0.023 ohm^(-1) cm^(2) eq^(-1)`

Answer

A

Explanation

`kappa=Cxxl/A=1/250xx1.15=4.6xx10^(-3) ohm^(-1) cm^(-1)`
`Lambda_(e) =kappaxx1000/N =4.6xx10^(-3) xx1000/1=4.6 ohm^(-1) cm^(2) eq^(-1)`