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The oxidation potential of a hydrogen el...

The oxidation potential of a hydrogen electrode at `pH = 10` and `P_(H_(2)) =1` is

A

0.51 V

B

0.00 V

C

`+ 0.59 V`

D

0.059 V

Text Solution

Verified by Experts

The correct Answer is:
C
`E_(ox)=E_(ox)^(@)-0.0591/n "log" ([H^(+)])/(pH_(2))`
`=0-0.0591/1 "log"10^(-10)/1 =0.59 V`
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