A certain quantity of electricity deposits 0.54 g of Ag from silver nitrate solution. What volume of hydrogen will be liberated by the same quantity of electricity at `27^(@)C` and 750 mm of Hg pressure ?

Explanation

`("Mass of "H_(2))/("Mass of Ag")=("Eq. mass of "H_(2))/("Eq. mass of Ag")`
Mass of `H_(2)=(1 xx 0.54)/108=0.005 g`
Volume of `H_(2)=(0.005xx0.0821xx300xx760)/(2 xx 750) (V=w/M.(RT)/P)`
`=0.06234` litre