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The electrode potentials of two half rea...

The electrode potentials of two half reactions are as follows :
`{:(Fe^(3+)+e^(-) rarr Fe^(2+),,,E^(@)=+0.76" volt"),(Ce^(4+)+e^(-) rarr Ce^(3+),,,E^(@)=+1.60" volt"):}`
Giving reason, describe if `Ce^(3+)` can be oxidised by `Fe^(3+)`.

Text Solution

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`Ce^(3+)+Fe^(3+) rarr Ce^(4+)+Fe^(2+)`
`Ce^(3+) rarr Ce^(4+) +e^(-) ("oxidation"), E^(@)=-1.60` volt
`Fe^(3+) +e^(-) rarr Fe^(2+)`
Adding both, `E^(@)` of the reaction `=-0.84` volt
The oxidation of `Ce^(3+)` by `Fe^(3+)` is not possible.
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