Home
Class 12
CHEMISTRY
Calculate the emf of the cell Cr|Cr^(3...

Calculate the emf of the cell
`Cr|Cr^(3+) (0.1 M) ||Fe^(2+) (0.01 M)|Fe`
`("Given: "E_(Cr^(3+)//Cr)^(@)=- 0.75" volt, "E_(Fe^(2+)//Fe)^(@)=-0.45" volt")`

Text Solution

Verified by Experts

The correct Answer is:
0.261 volt
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    OP TANDON|Exercise OBJECTIVE TYPE QUESTION (LEVEL -A)|194 Videos
  • ELECTROCHEMISTRY

    OP TANDON|Exercise OBJECTIVE TYPE QUESTION (LEVEL -B)|52 Videos
  • ELECTROCHEMISTRY

    OP TANDON|Exercise ILLUSTRATIONS|28 Videos
  • COORDINATION COMPOUNDS

    OP TANDON|Exercise SBJECTIVE TYPE|96 Videos
  • HALOALKANES AND HALOARENES

    OP TANDON|Exercise Single Interger answer type questions|14 Videos

Similar Questions

Explore conceptually related problems

Calculate the e.m.f. of the cell, Cr//Cr^(3+)(0.1 M) || Fe^(2+)(0.01 M)//Fe "Given" : E_(Cr^(3+)//Cr)^(@)=-0.75" V ", E_(Fe^(2+)//Fe)^(@)=-0.45" V " "Cell reaction" : 2Cr(s)+3Fe^(2+)(aq) to 2Cr^(3+)(aq)+3Fe(s) {"Hint". E_(cell)=E_(cell)^(@)-(0.0591V)/(6)"log"([Cr^(3+)]^(2))/([Fe^(2+)]^(3)}

Calculate the e.f.m of the cell Cr|Cr^(3+)(0.1M)||Fe^(2+)(0.01M)|Fe [given that E_(Cr^(3+)//Cr)^(@)=-0.75,E_(Fe^(2+)//Fe)^(@)=-0.45V]

What is the value of E^(@) cell in the following reaction? Cr|Cr^(3+) (0.1 M)||Fe^(2+) (0.01 M)|Fe Given, E_(Cr^(3+)//Cr)^(@)=-0.74 V, E_(Fe^(2+)//Fe)^(@)=-0.44 V

The EMF of the cell, Cr|Cr^(+3) (0.1M) ||Fe^(+2) (0.01M)|Fe (Given: E^(0) Cr^(+3)|Cr =- 0.75 V, E^(0) Fe^(+2)|Fe =- 0.45 V)

What is the potential for the cell Cr|Cr^(3+)(0.1M)||Fe^(2+)(0.01M)|Fe E^(@)Cr^(3+)// Cr=-0.74V , E^(@)Fe^(2+)//Fe=-0.44V

Calculate e.m.f. of the following cell at 298 K, 2Cr(s)+3Fe^(2+)(0.1 M) to 2Cr^(3+)(0.01 M)+3Fe(s) ("Given" : E_((Cr^(3+)//Cr))^(@)=-0.74" V ", E_((Fe^(2+)//Fe))^(@)=-0.44" V ")

OP TANDON-ELECTROCHEMISTRY-PRACTICE PROBLEMS
  1. Calculate equilibrium constant for the following reaction : Zn+CuSO(...

    Text Solution

    |

  2. For the cell reaction, Ni|Ni^(2+)||Ag^(+)|Ag Calculate the equilib...

    Text Solution

    |

  3. Calculate the emf of the cell Cr|Cr^(3+) (0.1 M) ||Fe^(2+) (0.01 M)|...

    Text Solution

    |

  4. Calculat the equilibrium constant for the reaction, Zn(s)+Ag(2)O(s)+...

    Text Solution

    |

  5. The standard reduction potential of Ag^(+)|Ag electrode is 0.80 volt. ...

    Text Solution

    |

  6. Derive Nernst equation for the cell. Ni(s)|Ni^(2+) (aq. 0.1 M)||Ag^(...

    Text Solution

    |

  7. Determine the equilibrium constant of the following reaction at 298 K ...

    Text Solution

    |

  8. An excess of Hg was added to 10^(-3) M acidified solution of Fe^(3+) i...

    Text Solution

    |

  9. The emf of the cell, Ag|AgI (0.05) MKI|| (0.05) M AgNO(3)|Ag is 0....

    Text Solution

    |

  10. At equimolar concentrations of Fe^(2+) and Fe^(3+), what must [Ag^(+)]...

    Text Solution

    |

  11. Using Nernst equation for the cell reaction, Pb+Sn^(2+) rarr Pb^(2+)...

    Text Solution

    |

  12. Determine the potential of a Daniell cell, initially containing 1.00 L...

    Text Solution

    |

  13. Calculate the standard potential for the reaction, Hg(2)Cl(2)+Cl(2) ...

    Text Solution

    |

  14. Given : {:(Cu^(2+)+e^(-) rarr Cu^(+),,E^(@)=0.15" volt"),(Cu^(+)+e^(...

    Text Solution

    |

  15. What is the standard electrode potential for the electrode MnO(4)^(-)/...

    Text Solution

    |

  16. What ratio of Pb^(2+) to Sn^(2+) concentration is needed to reverse th...

    Text Solution

    |

  17. For the cell Mg|Mg^(2+)||Ag^(+)|Ag, calculate the equilibrium constant...

    Text Solution

    |

  18. Determine the potential for the cell : Pt|Fe^(2), Fe^(3+)||Cr(2)O(7)...

    Text Solution

    |

  19. For the measurement of the solubility product of AgCl the following ce...

    Text Solution

    |

  20. Excess of AgCl is added to 0.1 M solution of KBr at 298 K. Calculate t...

    Text Solution

    |