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The standard reduction potential of Ag^(...

The standard reduction potential of `Ag^(+)|Ag` electrode is 0.80 volt. Calculate the standard electrode potential of `Cl^(-)|AgCl|Ag` at `25^(@)C`. Given solubility product, `K_(sp)(AgCl)=1.8xx10^(-10)`.

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`E_(cell)^(@)=0.0591xxlog [Ag^(+)][Cl^(-)]=0.591 log K_(sp) (AgCl)`
`E_(cell)^(@)=-0.576` volt
`E_(cell)^(@)`= Oxid. pot. anode + Red. pot. cathode
Red. Pot. Cathode `[Cl^(-)|AgCl|Ag]=-0.576-(-0.80)`
`=-0.576+0.80=0.224` volt
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