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The emf of the cell, Ag|AgI (0.05) MKI...

The emf of the cell,
`Ag|AgI (0.05) MKI|| (0.05) M AgNO_(3)|Ag`
is 0.788 volt. Calculate the solubility product of AgI.

Text Solution

Verified by Experts

The correct Answer is:
`1.10xx10^(-16)`
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