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Given : {:(Cu^(2+)+e^(-) rarr Cu^(+),,...

Given :
`{:(Cu^(2+)+e^(-) rarr Cu^(+),,E^(@)=0.15" volt"),(Cu^(+)+e^(-) rarr Cu,,E^(@)=0.5" volt"):}`
Calculate potential for `Cu^(2+)+2e^(-) rarr Cu`.

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The correct Answer is:
0.325 volt
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If for the half cell reaction E^(@) value are given Cu^(2+)+e^(-)rarrCu^(+),E^(@)=0.15V Cu^(2+)+2e^(-)rarrCu^(+),E^(@)=0.34V calculate E^(@) of the half cell reaction Cu^(+)+e^(-)rarrCu

Given: (i) Cu^(2+)+2e^(-) rarr Cu, E^(@) = 0.337 V (ii) Cu^(2+)+e^(-) rarr Cu^(+), E^(@) = 0.153 V Electrode potential, E^(@) for the reaction, Cu^(+)+e^(-) rarr Cu , will be

Cu^(+) + e^(-) rightarrow Cu , E^(@) = x1volt , Cu^(2+) + 2e^(-) rightarrow Cu , E^(@) = x_(2) volt, then for Cu^(2+) + e^(-) rightarrow Cu^(+), E^(@) (volt) will be :

Goven : (i) CU^(2+) + 2e^- rarr Cu, E^@ = 0.337 V (ii) Cu^(2+) +e^- rarr Cu^(+) , E^2=0.1 5 3 V .

Given that standard potential for the following half - cell reaction at 298 K, Cu^(+)(aq)+e^(-)rarr Cu(s), E^(@)=0.52V Cu^(2+)(aq)+e^(-)rarrCu^(+)(aq), E^(@)=0.16V Calculate the DeltaG^(@)(kJ) for the eaction, [2Cu^(+)(aq)rarr Cu(s)+Cu^(2+)]

E^@ values for the half cell reactions are given below : Cu^(2+) + e^(-) to Cu^(+) , E^@ =0.15 V Cu^(2+) + 2e^(-) to Cu, E^@ =0.34 V What will be the E^@ of the half-cell : Cu^(+) + e^(-) to Cu ?

Cu^(+) + e rarr Cu, E^(@) = X_(1) volt, Cu^(2+) + 2e rarr Cu, E^(@) = X_(2) X_(2) volt For Cu^(2+) + e rarr Cu^(+), E^(@) will be :

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