The equivalent conductivity of `0.1 N CH_(3) COOH " at " 25^(@)C` is 80 and at infinite dilution 400 `ohm^(-1)`. The degree of dissociation of `CH_(3)COOH` is:

Options

A. 1
B. `0.2`
C. `0.1`
D. `0.5`

Answer

To find the degree of dissociation (α) of acetic acid (CH₃COOH), we can use the formula:

\[ \alpha = \frac{\text{Equivalent Conductivity at given concentration}}{\text{Equivalent Conductivity at infinite dilution}} \]

Given:
- Equivalent conductivity at 0.1 N (concentration) = 80 ohm⁻¹
- Equivalent conductivity at infinite dilution = 400 ohm⁻¹

Now, substituting the values into the formula:

\[ \alpha = \frac{80 \, \text{ohm}^{-1}}{400 \, \text{ohm}^{-1}} \]

Calculating this gives:

\[ \alpha = \frac{80}{400} = 0.2 \]

Thus, the degree of dissociation of CH₃COOH is 0.2.

### Final Answer:
The degree of dissociation (α) of CH₃COOH is 0.2.

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