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The cell , Zn | Zn^(2+) (1M) || Cu^(2+) ...

The cell , `Zn | Zn^(2+) (1M) || Cu^(2+) (1M) Cu (E_("cell")^@ = 1. 10 V)`,
Was allowed to be completely discharfed at `298 K `. The relative concentration of `2+` to `Cu^(2+) [(Zn^(2=))/(Cu^(2+))]` is :

A

`9.65 xx 10^(4)`

B

antilog (24.08)

C

`37.3`

D

`10^(37.3)`

Text Solution

Verified by Experts

The correct Answer is:
D
`E = E^(@) - (0.059)/(2) log.([Zn^(2+)])/([Cu^(2+)])`
`0 = 1.10 - (0.059)/(2) log. ([Zn^(2+)])/([Cu^(2+)])`
`log .([Zn^(2+)])/([Cu^(2+)]) = 37.3 :. ([Zn^(2+)])/([Cu^(2+)]) = 10^(37.3)`
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