The production potential of hydrogen half-cell will be negative if:

Options

A. `pH_(2) = 2 atm` and `[H^(+)] = 2.0 M`
B. `pH_(2) = 1 atm` and `[H^(+)] = 2.0 M`
C. `pH_(2) = 1 atm` and `[H^(+)] = 1.0 M`
D. `pH_(2) = 2atm` and `[H^(+)] = 1.0 M`

Answer

D

Explanation

`E = E_(H^(+)//H_(2))^(@) - (0.059)/(n) log.(pH_(2))/([H^(+)]^(2))`
`= 0-(0.059)/(2) log.(pH_(2))/([H^(+)]^(2)) = - (0.059)/(2) log.(2)/(1^(2)) = -ve`