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Electrolysis of dilute aqueous NaCl solu...

Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milli ampere current. The time required to liberate 0.01 mol of `H_(2)` gas at the cathode is (1 Faraday=96500 C `"mol"^(-1)`)

A

`9.65xx10^(4)` sec

B

`19.3xx10^(4)` sec

C

`28.95xx10^(4)` sec

D

`38.6xx10^(4)` sec

Text Solution

Verified by Experts

The correct Answer is:
B
Mass of 0.01 mol `H_(2)=0.02 g`
`W=(ItE)/(96500)`
`0.02=(10xx10^(-3) xxtxx1)/(96500)`
`t=19.3 xx 10^(4)` sec
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Electrolysis of dilute aqueous NaCl solution was carried out by passing 10mA current. The time required to liberate 0.01mol of H_(2) gas at the cathode is (1F=96500C mol ^(-1))

Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 mA current. The time required to liberate 0.01 mole of H_2 gas at the cathode is : (1f= 96500C mol^(-1)

Electrolysis of dilute aqueous NaCl solution was carried out by passing 10A current. The time required (in seconds) to liberate 0.01 mole of H2 gas at the cathode is: [IF = 96500 C]

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