Given `E_(Cl_(2)//Cl^(-))^(@)=1.36V,E_(Cr^(3+)//Cr)^(@)=-0.74V`
`E_("Cr_(2)O_(7)^(2-)//Cr^(3+))^(@)=1.33V,E_(MnO_(4)^(-)//Mn^(2+))^(@)=1.51V`
Among the following, the strongest reducing agent is

Options

A. `Cr^(3+)`
B. `Cl^(-)`
C. `Cr`
D. `Mn^(2+)`

Answer

C

Explanation

`{:("Species","Oxidation Potential"),(Cr^(3+),E_(Cr^(3+)//Cr_(2)O_(7)^(2-))^(@)=-1.33 V),(Cl^(-),E_(Cl^(-)//Cl_(2))^(@)=-1.36 V),(Cr,E_(Cr//Cr^(3+))^(@)=+0.74 V),(Mn^(2+),E_(Mn^(2+)//MnO_(4)^(-))^(@)=-1.51 V):}`
Greater is the positive value of standard oxidation potential more is reducing behavious. Thus, Cr will be strongest reducing agent.